If

Question

f(x) = 8x2 − x3,
find f '(2) and use it to find an equation of the tangent line to the curve
y = 8x2 − x3
at the point (2, 24).

Answer 1

f' = 16x-3x^2
f'(2) = 32-24 = 8
now you have a point and a slope, so use the point-slope form of the line.

Answer 2

So start by taking the derivative of f(x)
Then sub in f'(2) into the derivative you found : )

Answer 3

Awesome help oobleck : )
I am so happy we are on the same team : )
Yours in Mathematical fun, Ms Pi