Question

The reaction of 5.25 g of Carbon with excess O2 yields 10.2 g of CO2. What is the percent yield of this reaction?

Answer 1

find moles of C and moles CO2 ... should be the same in a complete reaction

percent yield = (moles CO2 / moles C) * 100%

Answer 2

C + O₂ => CO₂
(5.25-gC/12g/mol) = 0.4375 mole C => 0.4375 mole CO₂ x 44 g/mole = 19.25 g (Theoretical Yield)
%Yield = [Actual Yield / Theoretical Yield] x 100% = (10.2-g/19.25-g) x 100% ≈ 53% Yield