Question
the sum of two number is 40. when 3¼ times the larger number is subtracted from 5½ times the smaller, the difference is -25. find the two numbers
Answers
n + m = 40 ...13 n + 13 m = 520
11/2 n - 13/4 m = -25 ... 22 n - 13 m =-100
11/2 n - 13/4 m = -25 ... 22 n - 13 m =-100
Let's the be x, while the smaller be c
x+y=40
5.5y-3.25=-25
5.5y-3.25=(40-y)=-27
5.5y-130-3.25y=-27
5.5y-3.25y=-27+130
8.75y=105
y=105/8.75
y=12
c+12=40
c=40-12
c=28
x+y=40
5.5y-3.25=-25
5.5y-3.25=(40-y)=-27
5.5y-130-3.25y=-27
5.5y-3.25y=-27+130
8.75y=105
y=105/8.75
y=12
c+12=40
c=40-12
c=28
Related Questions
One number exceeds another by 12 . if five times the smaller number is subtracted from three times...
the sum of 2 numbers is 83. three times the smaller number is subtracted from the larger number is 1...
One number is twice the other.when the larger number is subtracted from 50.the result is two more th...
Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number...