Asked by Branden
Find all the points of inflection of the function: f(x)=x^3-3x^2-x+7
Answers
Answered by
Reiny
f'(x) = 3x^2 - 6x - 1
f''(x) = 6x - 6
= 0 for points of inflection
6x = 6
x = 1
then f(1) = 1-3-1+7 = 4
point of inflection is (1,4)
f''(x) = 6x - 6
= 0 for points of inflection
6x = 6
x = 1
then f(1) = 1-3-1+7 = 4
point of inflection is (1,4)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.