Asked by Branden
Find all the points of inflection of the function: f(x)=x^3-3x^2-x+7
Answers
Answered by
Reiny
f'(x) = 3x^2 - 6x - 1
f''(x) = 6x - 6
= 0 for points of inflection
6x = 6
x = 1
then f(1) = 1-3-1+7 = 4
point of inflection is (1,4)
f''(x) = 6x - 6
= 0 for points of inflection
6x = 6
x = 1
then f(1) = 1-3-1+7 = 4
point of inflection is (1,4)
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