Asked by Annaa

The age of a man 7 years ago was seven times the age of his son. Father's age after 3 years will be three times the age of the son. Find their present ages.
Answered by oobleck
If the father is f and the son is s, then we know
f-7 = 7(s-7)
f+3 = 3(s+3)
Now just solve for f and s
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