Question
a brown mouse is crossed with hertozygous black mouse. if the mother has a litter of four, what are thae chances all of them will be brown?
http://en.wikipedia.org/wiki/Punnett_square
do you have more specifics? because that didn't help a bit
There is a 50% chance the the litter will be brown.
Assuming that the heterozygous mouse has one recessive brown gene (b) and one dominant black gene (B) and the brown mouse is bb, <B>Kyonia</B> is right <I>for one birth</I>.
Thus the brown mouse can give either b or b, while the black mouse can give either b or B. Plug the symbols into the Punnett square to see how we arrived at the conclusion.
However, the question asked for the probability that <B>all</B> of them are brown. To find the probability that <I>all</I> events will occur, you need to <I>multiply</I> the probability of the individual events, in this case, the 4 mice. You can do the calculations.
I hope this helps. Thanks for asking.
http://en.wikipedia.org/wiki/Punnett_square
do you have more specifics? because that didn't help a bit
There is a 50% chance the the litter will be brown.
Assuming that the heterozygous mouse has one recessive brown gene (b) and one dominant black gene (B) and the brown mouse is bb, <B>Kyonia</B> is right <I>for one birth</I>.
Thus the brown mouse can give either b or b, while the black mouse can give either b or B. Plug the symbols into the Punnett square to see how we arrived at the conclusion.
However, the question asked for the probability that <B>all</B> of them are brown. To find the probability that <I>all</I> events will occur, you need to <I>multiply</I> the probability of the individual events, in this case, the 4 mice. You can do the calculations.
I hope this helps. Thanks for asking.