I have a couple questions I answer for home work could some look atthem and tell me If I am doing them right I also am having problems understanding the variance and standard deviation are the site you can suggest that would help with this I need a step by step help
11. For the following scores, find the (a) mean,
Usually the best measure of central tendency is the ordinary average, the sum of all
the scores divided by the number of scores. In statistics, this is called the mean. The
average, or mean, of a group of scores is a representative value.
2+ 2 +0 + 5 + 1+ 4+ 1+ 3+ 0+ 0+ 1+ 4+ 4+ 0+ 1+ 4+ 3+ 4+ 2+ 1+ 0= 42
42/21=2
(b) median, Another alternative to the mean is the median. If you line up all the scores from
lowest to highest, the middle score is the median.
0 ,0,0,0,0, 1,1,1,1,1,2,2,2,3,3,4,4,4,4,4,5
Median 2
(c) sum of squared deviations,
0x0=0, 1x1=1, 2x2=4,3x3=9, 4x4=16, 5x5=25
0+0+0+0+0+1+1+1+1+1+4+4+4+9+9+16+16+16+16+16+25= 140
(d) variance
(e) standard deviation:
14.
On a standard measure of hearing ability, the mean is 300 and the standard deviation
is 20. Give the Z scores for persons who score
(a) 340
z=(340-300)/(20)
z=(40)/(20)
z=2
(b) 310
z=(310-300)/(20)
z=(10)/(20)
z=(1)/(2)
(c)260.
z=(260-300)/(20)
z=(-40)/(20)
z=-(40)/(20)
z=-2
Give the raw scores for persons whose Z scores on this test are
(d) 2.4
2.4*20+300=x
x=2.4*20+300
x=48+300
x=348
(e)1.5
1.5*20+300=x
x=1.5*20+300
x=30+300
x=330
(f) 0
0*20+300=x
x=0*20+300
x=0+300
x=300
(g) -4.5.
-4.5*20+300=x
x=-4.5*20+300
x=-90+300
x=210
any help would be appreciated
Thank you
3 answers
the variance is the sum of the squares of the deviations from the mean.
Since most of you data values hover around 0-5, it is hard to tell whether you squared the differences or the actual data values.
I see a 5x5, so it appears that you simply squared the data values.
take each data value, subtract it from the mean, then square it.
now add these up, they should all be positive, and divide by 21
That is your variance.
the standard deviation is the square root of that variance.
I don't know at what level of sophistication your study of statistic is, but there is a difference in how the variance and standard deviations are calculated.
If you "google" variation and standard deviation, most pages will explain that difference
Here is a page that gives a short explanation
http://www.chem.utoronto.ca/coursenotes/analsci/StatsTutorial/MeasMeanVar.html
Your last question shows up as imcomplete.
A Z score is found by:
(your score - mean)/standard deviation
so suppose one of your values is 350, then the z-score for that data value would be (350 - 300)/20 or 2.5
3.0, 3.4, 2.6, 3.3, 3.5, 3.2