Asked by Valeriya
Car X passes car Y on a motorway. Car X is travelling at 1.5 times the speed of car Y. The mass of car X is 5/4 of the mass car Y. How do the kinetic energies of the two cars compare?
(the answer is KE (X) = 1.80 * KE (Y))
(the answer is KE (X) = 1.80 * KE (Y))
Answers
Answered by
bobpursley
KEx=1/2 m v^2=1/2 1.25 (1.5)^2
KEy=1/2 m v^2
kex/key=1.5^2 * 1.25 Not your answer.
Are you certain it did not read "The mass of car Y is 5/4 of the mass car X" That would give you the answer you proposed ...4/5 * 1.5^2
KEy=1/2 m v^2
kex/key=1.5^2 * 1.25 Not your answer.
Are you certain it did not read "The mass of car Y is 5/4 of the mass car X" That would give you the answer you proposed ...4/5 * 1.5^2
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