Yes, that's correct. Note that
T = p*v/(n*R)
so T = 273 K when p is 1 atm, v is 22.4 L, and n = 1. So you have reduced v from 22.4 to 0.5 AND you have reduced the number even more by doubling the denominator.
A sample of an ideal gas consists of 2 moles, pressure = 1 atm, volume = 0.5 liters
Find the temperature
pV=nRT
T = p*V/(n*R)
T = 1 atm * 0.5 liters / (2 moles * .08206 L atm K^-1 * mol^-1)
T = 3.04 K
Did I do that problem correctly? That temperature seems unrealistically low.
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