Asked by Gash
Find the mean and variance of the first n natural numbers.
Answers
Answered by
Anonymous
Their sum is ∑k = n(n+1)/2
So, the mean is easy, right?
The sum of their squares is ∑k^2 = n(n+1)(2n+1)/6
Now you can get the variance using the usual formula.
So, the mean is easy, right?
The sum of their squares is ∑k^2 = n(n+1)(2n+1)/6
Now you can get the variance using the usual formula.
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