Find the distance, in meters, a particle travels in its first 10 seconds of travel, if it moves according to the velocity equation v(t)= 49 − 9.8t (in meters/sec)
a) -49
b)0
c) 245
d) 441
2 answers
answer c= 245???
B
integrate from 0..10 49-9.8t dt = 49t-4.9t^2
integrate from 0..10 49-9.8t dt = 49t-4.9t^2
1 answer