Asked by Alice

Find the distance, in meters, a particle travels in its first 10 seconds of travel, if it moves according to the velocity equation v(t)= 49 − 9.8t (in meters/sec)

a) -49
b)0
c) 245
d) 441
Answered by Alice
answer c= 245???
Answered by oobleck
B
integrate from 0..10 49-9.8t dt = 49t-4.9t^2
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