Asked by tom
                evaluate the improper interval with an interior discontinuity 
dx/x^3 from -1 to 2
            
        dx/x^3 from -1 to 2
Answers
                    Answered by
            tom
            
    integral ** not interval 
    
                    Answered by
            oobleck
            
    dx/x^3 is just x^-3 dx
so you just use the power rule:
∫dx/x^3 = -1/(2x^2)
Now we run into a snag, since -1/(2x^2) is undefined at x=0
So, we have to evaluate the limits from left and right.
Unfortunately, they also do not exist, so the integral does not converge.
    
so you just use the power rule:
∫dx/x^3 = -1/(2x^2)
Now we run into a snag, since -1/(2x^2) is undefined at x=0
So, we have to evaluate the limits from left and right.
Unfortunately, they also do not exist, so the integral does not converge.
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