Asked by tom
evaluate the improper interval with an interior discontinuity
dx/x^3 from -1 to 2
dx/x^3 from -1 to 2
Answers
Answered by
tom
integral ** not interval
Answered by
oobleck
dx/x^3 is just x^-3 dx
so you just use the power rule:
∫dx/x^3 = -1/(2x^2)
Now we run into a snag, since -1/(2x^2) is undefined at x=0
So, we have to evaluate the limits from left and right.
Unfortunately, they also do not exist, so the integral does not converge.
so you just use the power rule:
∫dx/x^3 = -1/(2x^2)
Now we run into a snag, since -1/(2x^2) is undefined at x=0
So, we have to evaluate the limits from left and right.
Unfortunately, they also do not exist, so the integral does not converge.
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