Question
In a recent health study it was claimed that 18% of americans are underwieght.If 4 americans randomly selected what is the probability that
a. that all will be underweight
b.none will be underweight
c. at least one will be underweight
a. that all will be underweight
b.none will be underweight
c. at least one will be underweight
Answers
bobpursley
pr(a.)=18/100*18/100*18/100*18/100
I will be happy to check the others. On the last, remember there are four ways the combination can occur
I will be happy to check the others. On the last, remember there are four ways the combination can occur
bobpursley
Sorry, on the last, you could have
4 ways to have one underweight
UFFF, FUFF, FFUF, FFFU
Ways to have two U
UUff, UfUf, UffU, FUUf, FUfU, FfUU
Ways to have three U
UUUf, UfUU, FUUU, UUfU
Ways to have four U.
UUUU
4 ways to have one underweight
UFFF, FUFF, FFUF, FFFU
Ways to have two U
UUff, UfUf, UffU, FUUf, FUfU, FfUU
Ways to have three U
UUUf, UfUU, FUUU, UUfU
Ways to have four U.
UUUU