Asked by Alice
                Express the um using sigma notation:
1 +3/4 +5/9+ 7/16+ 9/25
            
        1 +3/4 +5/9+ 7/16+ 9/25
Answers
                    Answered by
            oobleck
            
    what, you don't recognize
1,3,5,7,9,...
1,4,9,16,25,...
??
∑ (2k-1)/k^2
    
1,3,5,7,9,...
1,4,9,16,25,...
??
∑ (2k-1)/k^2
                    Answered by
            Anonymous
            
    maybe
a(1) = 1
a(n+1) = (a(n)+2)/n^2
sum = sigma from n=1 to n = 5 of a(n)
    
a(1) = 1
a(n+1) = (a(n)+2)/n^2
sum = sigma from n=1 to n = 5 of a(n)
                    Answered by
            Anonymous
            
    oobleck gave better answer.
    
                    Answered by
            Alice
            
    Thank you very much :)
    
                    Answered by
            4TheLoveOfPhysics
            
    What oobleck said, but with the upper and lower limits will give:
n=5
∑ (2k-1)/k^2
n=1
    
n=5
∑ (2k-1)/k^2
n=1
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