Asked by venusthedalek
Which system of inequalities is represented by the graph?
A system of inequalities is graphed on a coordinate plane. One line passes through left parenthesis negative 5 comma 3 right parenthesis and left parenthesis 0 comma 8 right parenthesis. The second line passes through left parenthesis negative 5 comma 7 right parenthesis and left parenthesis 0 comma negative 8 right parenthesis. The area below the first line and above the second line, which is on the right side of the graph, is shaded.
A.
y ≥ x + 8 and 8x + y ≥ 8
B.
y ≤ x + 3 and 8x + y ≤ –8
C.
y ≤ –x + 8 and 3x + y ≥ –8
D.
y ≤ x + 8 and 3x + y ≥ –8
A system of inequalities is graphed on a coordinate plane. One line passes through left parenthesis negative 5 comma 3 right parenthesis and left parenthesis 0 comma 8 right parenthesis. The second line passes through left parenthesis negative 5 comma 7 right parenthesis and left parenthesis 0 comma negative 8 right parenthesis. The area below the first line and above the second line, which is on the right side of the graph, is shaded.
A.
y ≥ x + 8 and 8x + y ≥ 8
B.
y ≤ x + 3 and 8x + y ≤ –8
C.
y ≤ –x + 8 and 3x + y ≥ –8
D.
y ≤ x + 8 and 3x + y ≥ –8
Answers
Answered by
R_scott
find the equations of the two lines
... probably easiest to start with point-slope , then convert to slope-intercept
the solution area is between the two lines
I'll be happy to check your work
... probably easiest to start with point-slope , then convert to slope-intercept
the solution area is between the two lines
I'll be happy to check your work
Answered by
venusthedalek
thx
Answered by
Nobody
what did you get @venusthedalek
Answered by
tylersux
tyler you suck
Answered by
Deez
who's candice?
Answered by
Answer
The answer is y<=x+8 and y>=-3x-8
Answered by
nonya buisness
@Answer is correct just took the test
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