Asked by BTS
1. Tell whether the lines for the pair of equations are parallel, perpendicular, or neither. Y=-3/4x-2
A. Parallel
B. Perpendicular*
C. Neither
2. Write the equation of a line that is perpendicular to the given line and that passes through the given point. Y-3=-1/5 (x+2); (-2, 7)
A. y=5x+7
B. y=5+17
C. y=(1/5)x-2
D. y=-2x+3
A. Parallel
B. Perpendicular*
C. Neither
2. Write the equation of a line that is perpendicular to the given line and that passes through the given point. Y-3=-1/5 (x+2); (-2, 7)
A. y=5x+7
B. y=5+17
C. y=(1/5)x-2
D. y=-2x+3
Answers
Answered by
Bosnian
Do you know at least to write a question?
1.
pair of equations
y = - 3 / 4 x - 2
What is the other equation?
2.
y = 5 + 17 ???
2.
y - 3 = - 1 / 5 ( x + 2 )
y - 3 = - 1 / 5 x + 2 / 5
Add 3 to both sides
y - 3 + 3 = - 1 / 5 x + 2 / 5 + 3
y = - 1 / 5 x + 2 / 5 + 3
y = - 1 / 5 x + 2 / 5 + 15 / 5
y = - 1 / 5 x + 17 / 5
y = m x + b
y = - 1 / 5 x + 17 / 5
m = - 1 / 5
A perpendicular line has a slope that is the negative reciprocal of this.
mp = - 1 / m = - 1 / ( - 1 / 5 ) = 5
You need the equation of the line through
( - 2 , 7 ) which means x = - 2 , y = 7
with slope 5
y = mp x + b
7 = 5 ∙ ( - 2 ) + b
7 = - 10 + b
Add 10 to both sides
7 + 10 = - 10 + b + 10
17 = b
b = 17
y = m x + b
y = 5 x + 17
1.
pair of equations
y = - 3 / 4 x - 2
What is the other equation?
2.
y = 5 + 17 ???
2.
y - 3 = - 1 / 5 ( x + 2 )
y - 3 = - 1 / 5 x + 2 / 5
Add 3 to both sides
y - 3 + 3 = - 1 / 5 x + 2 / 5 + 3
y = - 1 / 5 x + 2 / 5 + 3
y = - 1 / 5 x + 2 / 5 + 15 / 5
y = - 1 / 5 x + 17 / 5
y = m x + b
y = - 1 / 5 x + 17 / 5
m = - 1 / 5
A perpendicular line has a slope that is the negative reciprocal of this.
mp = - 1 / m = - 1 / ( - 1 / 5 ) = 5
You need the equation of the line through
( - 2 , 7 ) which means x = - 2 , y = 7
with slope 5
y = mp x + b
7 = 5 ∙ ( - 2 ) + b
7 = - 10 + b
Add 10 to both sides
7 + 10 = - 10 + b + 10
17 = b
b = 17
y = m x + b
y = 5 x + 17
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