Asked by FS
find how many real roots of, counting multiplicities x(x^2+16)(x^2-x-6)^2=0
please show how to get the answer. thank you
please show how to get the answer. thank you
Answers
Answered by
oobleck
x=0 has 1 root
x^2+16 = 0 has no real root
x^2-x-6 has 2 real roots and it is squared, so each is repeated.
So, add 'em up
The reason we always set everything to zero is that if any factors are multiplied to get zero, at least one of the factors must be zero.
x^2+16 = 0 has no real root
x^2-x-6 has 2 real roots and it is squared, so each is repeated.
So, add 'em up
The reason we always set everything to zero is that if any factors are multiplied to get zero, at least one of the factors must be zero.
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