I assume you can draw the Venn diagram. If not google is your friend.
If s passed science, then s+15 passed math. So,
s + (s+15) - 12 = 60-7
now you can answer questions 2,3
For #4, 60-7 passed something; 12 passed both, so 60-7-12 passed one or the other, but not both.
In an examination conducted for 60 candidates,the number of candidate who passed in Maths is 15 more than those who passed science and 7 failed both subject 12 candidates passed both subject
1.Draw a Venn diagram to illustrate this information
2.How many candidates passed Maths
3.How many candidates passed Science
4.Exactly one of the two subjects
12 answers
in an examination conducted for 60 candidates,the number who passed in mathematics are 15 more than those who passed in science and 7 failed in both subject. 12 candidates passed in both subject
I do not understand
Please take your time to explain
Please I don't get you!!
Please the solution for question above:
Let s=Science
(s+15)=Mathematics
U=60
Passed both subj=12
Failed in both sub=7
Now sum all together and equate to the U
(s+12+(15+s)+7=60
Therefore,s=13//.
Qns2,
Passed Math =(15+13)=28//
Qns3,
Passed Science=13
Qns4,
Passed one subject=(s-12,i.e 13-12=1//)+ (15+s-12,i.e 28-12=14//),therefore,one subject=(1+14=15)//
Let s=Science
(s+15)=Mathematics
U=60
Passed both subj=12
Failed in both sub=7
Now sum all together and equate to the U
(s+12+(15+s)+7=60
Therefore,s=13//.
Qns2,
Passed Math =(15+13)=28//
Qns3,
Passed Science=13
Qns4,
Passed one subject=(s-12,i.e 13-12=1//)+ (15+s-12,i.e 28-12=14//),therefore,one subject=(1+14=15)//
The Venn diagram
I need the Venn diagram for my homework
i dont understand
I don’t understand so pls explain it step by step
I want the Venn diagram for this question
U=60
M=X+15
S=X
(M n S)=12
(M n S)'=7
maths=(X+15)-12+X-12+12+7=60
=(X+3+X+7=60
=2X+10=60
=2X=60-10
=2X=50
2X/2=50/2
=X=25
Mathematics=X+15
=25+15
=40
Therefore,maths is 40
Science=X
=25
Therefore, science is 25
Exactly one of the subject=(40-12)+(25-12)
=28+13
=41
Therefore,41students passed in at least one subject
M=X+15
S=X
(M n S)=12
(M n S)'=7
maths=(X+15)-12+X-12+12+7=60
=(X+3+X+7=60
=2X+10=60
=2X=60-10
=2X=50
2X/2=50/2
=X=25
Mathematics=X+15
=25+15
=40
Therefore,maths is 40
Science=X
=25
Therefore, science is 25
Exactly one of the subject=(40-12)+(25-12)
=28+13
=41
Therefore,41students passed in at least one subject