Asked by David

In eight days, a certain amount of Vanadium-48, V^48, decays to 1 over square root 2 of its original amount. What is the half life of Vanadium-48?
Answered by Sydney Biddix
P*V = k
200*32 = V*40
Answered by oobleck
that would be 16 days, right?
1/√2 * 1/√2 = 1/2
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