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In eight days, a certain amount of Vanadium-48, V^48, decays to 1 over square root 2 of its original amount. What is the half life of Vanadium-48?
6 years ago

Answers

Sydney Biddix
P*V = k
200*32 = V*40
6 years ago
oobleck
that would be 16 days, right?
1/√2 * 1/√2 = 1/2
6 years ago

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