Asked by Christy

An industrial raw materials as the following composition by mass : iron = 28.1% chlorine = 35.7% and water of crystalization = 36.2%. Calculate the formula for the material given that Hydrogen is 1, oxygen is 16, chlorine is 35.5 and iron is 56.
Answered by bobpursley
Assume you have 1000 grams, calculate moles of each:
Fe: 281/56=5.01
Cl: 357/35.5=10.0
H2O: 36.2/(18)=2.0
Now divide these mole (ratios) by the lowest one:
Fe: 2.5
Cl:5
H2O:1
Now multiply by the LCM to give whole number ratios
Fe<sub>5</sub>Cl<sub>10</sub>. 2H<sub>2</sub>Od
FerrousChloride diHydrate
Answered by Eric
Cannot understand the answer
Answered by Anonymous
I not giving me what I want
Answered by Anonymous
Fe= 28.1
cl = 35.7
h2o= 36.2
find the mole,
fe
28.1/ 56
Answered by Anonymous
cont.d
fe
28.1/56= 0.501
cl
35.7/35.5=1.005
h2o
36.2/18=2.011
divide the mole ratios by the smallest mole
fe=1
cl=2
h2o=4
FeCl₂.4H₂O

Answered by MathEws
Sorry You mean 18/36.2 not 36.2/18 provided your previous examples.
Answered by TOLUWANI
U were told to find the empirical formula which goes thus

Fe=28.1%
Cl=35.7
Which is CH2O
SO TO FIND THE EMPIRICAL FORMULA WE HAVE,
ELEMENTS CL FE H O
REACTING
MASS
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