Question
How long will it take to deposit all the copper in 300 ml of 0.300(m) copper sulphate solution using current of o
0.750 ampere?
0.750 ampere?
Answers
bobpursley
mass of copper: .300*.300 moles=.09 moles
charge required= .09moles*avagradonumber (atoms/mole)*2electrons/atom*charge/electron
charge required= .09*6.02e23*2*1.6e-19
time= charge required/(.750coul/sec)
time= .09*6.02e23*2*1.6e-19 /.750 seconds
time= = 23116.8/3600 hours (a little less than 7 hours)
charge required= .09moles*avagradonumber (atoms/mole)*2electrons/atom*charge/electron
charge required= .09*6.02e23*2*1.6e-19
time= charge required/(.750coul/sec)
time= .09*6.02e23*2*1.6e-19 /.750 seconds
time= = 23116.8/3600 hours (a little less than 7 hours)