Asked by Anonymous
Find the derivative for k(x) = (5x4 + 2)(3sin x)
Answers
Answered by
bobpursley
f(uv)=v(f'(u) + u(f'(v))
(5x^4+2)(-3cosx) + 3sinx(4x^3)
(5x^4+2)(-3cosx) + 3sinx(4x^3)
Answered by
oobleck
Seems to me that
k(x) = (5x^4 + 2)(3sin x)
k' = (20x^3)(3sinx) + (5x^4+2)(3cosx)
= 15x^3(4sinx + xcosx) + 6cosx
k(x) = (5x^4 + 2)(3sin x)
k' = (20x^3)(3sinx) + (5x^4+2)(3cosx)
= 15x^3(4sinx + xcosx) + 6cosx
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