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60 cm of hydrogen diffused through a porous membrane in 10 minutes. The same volume of gas G diffused through the same membrane...Asked by Katherine
60cm3 of hydrogen diffused through a porous membrane in 10minutes.The same volume of gas G diffused through the same membrane in 37.4 minutes .Determine the relative molecular mass of G.(H=1)
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Answered by
bobpursley
rateG/rateH2 = sqrt (molmassH2/molemassG)
first, relative molmass H2=1
so molmassG=(rateH2/rateG)^2
but rates are inversley proportion to times of diffusion, so
relative molmassG=(3.74(^2=13.98 relative to H=1
actual molmass = twice that
first, relative molmass H2=1
so molmassG=(rateH2/rateG)^2
but rates are inversley proportion to times of diffusion, so
relative molmassG=(3.74(^2=13.98 relative to H=1
actual molmass = twice that
Answered by
Niklaus
Exactly
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