60cm3 of hydrogen diffused through a porous membrane in 10minutes.The same volume of gas G diffused through the same membrane in 37.4 minutes .Determine the relative molecular mass of G.(H=1)

Answer 1

rateG/rateH2 = sqrt (molmassH2/molemassG)
first, relative molmass H2=1
so molmassG=(rateH2/rateG)^2
but rates are inversley proportion to times of diffusion, so
relative molmassG=(3.74(^2=13.98 relative to H=1
actual molmass = twice that

Answer 2

Exactly