Asked by lun
(7.RP.3) When invested at an annual interest rate of 6% an account earned $180.00 of simple interest in one year. How much money was originally invested in account? (1 pt) *
a) $10.80
b) $108
c) $648
d) $30
e) $300
f) $3,000
a) $10.80
b) $108
c) $648
d) $30
e) $300
f) $3,000
Answers
Answered by
bobpursley
3000*.06=180
or more to the point, 180/.06=3000
or more to the point, 180/.06=3000
Answered by
Henry2
I = P*r*t = 180.
P*0.06 *1 = 180,
P = $3,000.
P*0.06 *1 = 180,
P = $3,000.
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