Asked by Anonymous
perimeter of 212 inches and the length is 82 more then the width. What are the dimensions?
Answers
Answered by
bobpursley
P=2L+2W
= 2(W+82)+2w=4W+164
212-164=4W
W=48/4=12
L=82+12
= 2(W+82)+2w=4W+164
212-164=4W
W=48/4=12
L=82+12
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