Asked by Taliyah

Given ABC with a = 7, b = 5, and mA= 19° , find the number of distinct solutions
I got 3 solutions
Answered by bobpursley
law of sines:
a/SinA=b/SinB=c/SinC
7/sin19deg=5/sinB
sinB=5*sin19deg/7=.233
B= arcsin.233=13.5 deg
Now you have A, B, a, b.
C=180-A-B
now solve for c using law of sines.
Answered by Reiny
Your data illustrates the ambiguous case.
How can you have 3 solutions ???
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