Multiply the 1st equation by -3 and you have
-3x+9y = 6
-3x+9y = 6
So, both equations describe the same line. Any solution to one is also a solution of the other.
x - 3y =-2
-3x +9y =2
4 answers
You are trying to solve two equations which are represented
by two parallel lines. There will be no solution, since parallel
lines will never intersect.
Here is what will happen:
multiply the first by 3, then add them
3x - 9y = 6
-3x + 9y = 2
0 = 2
this is a false statement.
If in solving 2 equations of this type, the variables drop out ....
1. you end up with a false statement, like ours above, there will
be no solution.
2. you end up with a true statement, then the two equations are
really just the same line, and there will be an infinite number of
solutions.
by two parallel lines. There will be no solution, since parallel
lines will never intersect.
Here is what will happen:
multiply the first by 3, then add them
3x - 9y = 6
-3x + 9y = 2
0 = 2
this is a false statement.
If in solving 2 equations of this type, the variables drop out ....
1. you end up with a false statement, like ours above, there will
be no solution.
2. you end up with a true statement, then the two equations are
really just the same line, and there will be an infinite number of
solutions.
Looks like both Steve and me both made silly
arithmetic errors.
My answer to the addition should have been
0 = 8 , but the conclusion and what follows is still valid.
arithmetic errors.
My answer to the addition should have been
0 = 8 , but the conclusion and what follows is still valid.
You mean 2 ≠ 9 ?
Dang!
Dang!