Asked by Kid
                Let's say I have the following:
(a/b) = (c/d)^(k-1)
If I know c, d, and k, then a/b can be calculated easily.
But what if c/d was the unknown, and a/b and k were known?
To find c/d, I was thinking:
ln(a/b) = ln(c/d)^(k-1)
ln(a/b) = (k-1)ln(c/d)
(ln(a/b))/(k-1) = ln(c/d)
e^(ln(a/b))/(k-1) = c/d
Did I do this correctly?
            
        (a/b) = (c/d)^(k-1)
If I know c, d, and k, then a/b can be calculated easily.
But what if c/d was the unknown, and a/b and k were known?
To find c/d, I was thinking:
ln(a/b) = ln(c/d)^(k-1)
ln(a/b) = (k-1)ln(c/d)
(ln(a/b))/(k-1) = ln(c/d)
e^(ln(a/b))/(k-1) = c/d
Did I do this correctly?
Answers
                    Answered by
            R_scott
            
    check your last step
(a/b)^[1 / (k - 1)] = [(c/d)^(k-1)]^[1 / (k - 1)] = c/d
    
(a/b)^[1 / (k - 1)] = [(c/d)^(k-1)]^[1 / (k - 1)] = c/d
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