going from (x,y,z) to (r,Ø,θ),
r^2 = x^2+y^2+z^2 = 1+3+12 = 16, so r=4
tanØ = y/x = -√3, so Ø = -π/3 or 2π/3
cosθ = z/r = √3/2, so θ = ±π/6
(1, −√3) is in QIV, so Ø = -π/3
z > 0, so θ = π/6
(r,Ø,θ) = (4,-π/3,π/6)
Looks good to me.
Convert the following point from rectangular to spherical coordinates:
(1, −√3, 2√3).
I found the answer to be (4, -pi/3, 0.5235987755983), but my online homework is stating that my middle coordinate (-pi/3) is incorrect. I put this into an online calculator and it's giving me the same answer. Am I missing something?
1 answer
1 answer