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how do I solve this problem

b + 18 + 3b = 74

2 answers

b + 18 + 3b = 74
b + 3b = 4b

4b + 18 = 74

Subtract 18 from 74

4b = 56
combine the b's first
4b+18=74
subtract 18 from each side
4b+18-18=74-18
4b=56
divide each side by 4
b= 14
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