Asked by tyger2020
A compound metal bar has 4 kg of copper making up the first third of the bar, while the remainder is made of 12 kg of lead. The bar is 3 meters in length. In addition, a mass of 2 kg is hung 1m from the left end of the bar, and a mass of 6 kg is hung 2m from the left end of the bar.
Where would a single rope have to be tied in order to hang the bar and masses so they would be in complete equilibrium?
Where would a single rope have to be tied in order to hang the bar and masses so they would be in complete equilibrium?
Answers
Answered by
bobpursley
The cg of the bar is at the 1.5m mark.
Summing moments about the left end.
2*1-Weight*x+16*1.5+6*2=0 check this. Clockwise moments
weight of bar is 16kg+8kg, the string pulls counterclockwise with force weight.
x= (2+24+12)/24= 38/24 m from the left end. check this.
Summing moments about the left end.
2*1-Weight*x+16*1.5+6*2=0 check this. Clockwise moments
weight of bar is 16kg+8kg, the string pulls counterclockwise with force weight.
x= (2+24+12)/24= 38/24 m from the left end. check this.
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