Asked by ZHAO
A player bounces a basketball on the floor, compressing it to 80.5 % of its original volume. The air (assume it is essentially N2 gas) inside the ball is originally at a temperature of 20.0∘C and a pressure of 2.00 atm. The ball's diameter is 24.4 cm .
Answers
Answered by
Steve
well, PV=kT
so PV/T is constant
(2.00)(V)/(20+273.15) = P(0.805V)/(T+273.15)
2.00/293.15 = 0.805P/(T+273.15)
You need more info to determine the new pressure or temperature.
so PV/T is constant
(2.00)(V)/(20+273.15) = P(0.805V)/(T+273.15)
2.00/293.15 = 0.805P/(T+273.15)
You need more info to determine the new pressure or temperature.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.