Asked by Tshering
Assume the mean height of the soldiers to be 68.22 inches with the variance of 10.8inches square. How many soldiers in the regiment of 1000 would you expect to be-(1.) Over 6 fee tall (2) below 5.5 feet? Assume height to be normally distributed. Given; Pr(0
<z<1.15) =0.3749, Pr(0<z<0.6756) =0.2501
<z<1.15) =0.3749, Pr(0<z<0.6756) =0.2501
Answers
Answered by
R_scott
standard deviation is √ variance
(1.) above the mean
... >72" ... Pr(0<z<1.15) = 0.3749 ... 0.5000 - 0.3749 = 0.1251
... 0.1251 * 1000 = 125 soldiers
(2) below the mean
... < 66" ... Pr(0<z<0.6756) = 0.2501 ... 0.2501 * 1000 = 250 soldiers
(1.) above the mean
... >72" ... Pr(0<z<1.15) = 0.3749 ... 0.5000 - 0.3749 = 0.1251
... 0.1251 * 1000 = 125 soldiers
(2) below the mean
... < 66" ... Pr(0<z<0.6756) = 0.2501 ... 0.2501 * 1000 = 250 soldiers
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