Asked by Myah

if you add 13.75 mL of 1.35M HCl to 22.80 mL of .955 M Ca(OH)2, will you neutralize all the Ca(OH)2?
Answered by DrBob222
mols HCl = M x L = ?
mols Ca(OH)2 = M x L = ?
2HCl + Ca(OH)2 ==> CaCl2 + 2H2O
1 mol Ca(OH)2 will neutralize 2 mols HCl.
Answered by bobpursley
you need twice the moles of acid as in the base;
moles base=.955*.0228 = .0217moles
moles acid: 1.35*.01375=.0186 moles
you do not have enough acid.
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