Asked by Lexy
PLEASE CHECK MY ANSWERS
1. Write f(x)=4^x-3 in f(x)=ab^x
F(x)=(1/64)(4)^x
2.solve for x 4^x+2=3^x-5
X=-log4/3(3888)
3.solve for x
Log5(x+4)+log5(8)=log8(64)
X=-7/8
1. Write f(x)=4^x-3 in f(x)=ab^x
F(x)=(1/64)(4)^x
2.solve for x 4^x+2=3^x-5
X=-log4/3(3888)
3.solve for x
Log5(x+4)+log5(8)=log8(64)
X=-7/8
Answers
Answered by
Steve
#1 ok
#2. almost. It is actually
-log(3888) / log(4/3)
#3. ok
#2. almost. It is actually
-log(3888) / log(4/3)
#3. ok
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