Asked by Ramesh
The discrete random variable W has probability density function (p.d.f.) given by:
P(W=w) = c(5-w) for w= 0, 1, 2, 3
Find c
I honestly have no idea how to start Any help is appreciated.
Thanks.
P(W=w) = c(5-w) for w= 0, 1, 2, 3
Find c
I honestly have no idea how to start Any help is appreciated.
Thanks.
Answers
Answered by
Steve
the probabilities must add up to 1. So,
c(5-0)+c(5-1)+c(5-2)+c(5-3) = 1
5c+4c+3c+2c = 1
c = 1/14
c(5-0)+c(5-1)+c(5-2)+c(5-3) = 1
5c+4c+3c+2c = 1
c = 1/14
Answered by
Damon
well, if that is the whole distribution, they have to add up to 1
5 c +4 c + 3 c + 2 c = 1
5 c +4 c + 3 c + 2 c = 1
Answered by
Ramesh
Oh wow it was a lot easier than I thought...
Thanks so much!
Thanks so much!
Answered by
Damon
You are welcome.
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