Question
Find the momentum of a 30.g stone that starts from rest and falls to the ground from a height of 20.m.
Answers
Damon
we want the speed times the mass.
a = -9.81 m/s^2
v = 0 - 9.81 t
h = 20 -9.81/2 t^2 = 20 - 4.9 t^2
h = 0 at ground so
4.9 t^2 = 20
then go back and use that t
v = -9.81 t
then finally
P = momentum = m v = 0.030 * v
a = -9.81 m/s^2
v = 0 - 9.81 t
h = 20 -9.81/2 t^2 = 20 - 4.9 t^2
h = 0 at ground so
4.9 t^2 = 20
then go back and use that t
v = -9.81 t
then finally
P = momentum = m v = 0.030 * v
Henry2
V^2 = Vo^2 + 2g*h = 0 + 19.6 * 20 = 392.
V = 19.8 m/s.
Momentum = M * V = 0.03 * V.
V = 19.8 m/s.
Momentum = M * V = 0.03 * V.