Asked by Dat
Find the momentum of a 30.g stone that starts from rest and falls to the ground from a height of 20.m.
Answers
Answered by
Damon
we want the speed times the mass.
a = -9.81 m/s^2
v = 0 - 9.81 t
h = 20 -9.81/2 t^2 = 20 - 4.9 t^2
h = 0 at ground so
4.9 t^2 = 20
then go back and use that t
v = -9.81 t
then finally
P = momentum = m v = 0.030 * v
a = -9.81 m/s^2
v = 0 - 9.81 t
h = 20 -9.81/2 t^2 = 20 - 4.9 t^2
h = 0 at ground so
4.9 t^2 = 20
then go back and use that t
v = -9.81 t
then finally
P = momentum = m v = 0.030 * v
Answered by
Henry2
V^2 = Vo^2 + 2g*h = 0 + 19.6 * 20 = 392.
V = 19.8 m/s.
Momentum = M * V = 0.03 * V.
V = 19.8 m/s.
Momentum = M * V = 0.03 * V.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.