Asked by Ande2
x2-x-6 is a factor of f(x)=3x3+px2+qx+6. Find the values of the constants p and q and state the zeros of f(x).
Answers
Answered by
Reiny
f(x) = 3x^3 + px^2 + qx + 6
If x^2-x-6 is a factor, so are (x-3) and (x+2)
that is f(3) = 0 and f(-2) = 0
f(3) = 81 + 9p + 3q + 6 = 0 ----> 3p + q = -29
f(-2) = -24 + 4p - 2q + 6 = 0 -----> 2p - q = 9
add them : 5p = -20
etc, take over ....
If x^2-x-6 is a factor, so are (x-3) and (x+2)
that is f(3) = 0 and f(-2) = 0
f(3) = 81 + 9p + 3q + 6 = 0 ----> 3p + q = -29
f(-2) = -24 + 4p - 2q + 6 = 0 -----> 2p - q = 9
add them : 5p = -20
etc, take over ....
Answered by
Micheal
Is correct, am very happy
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.