Asked by dlruhgbsdkufhbkdjhvb

a nonuniform rod of length L is placed along the x-axis at a distance h from the origin. the mass per unit length, lambda, varies according to the expression lambda = lambdainitial + Ax^2, where lambdainnitial and A are constants. find the force on a particle mass m placed at the origin.
Answered by Steve
well, the center of mass is at
∫x*λ(x) dx
----------------
∫λ(x) dx

right?
Then use that as r in F=GMm/r^2
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