The volume of 17.5 grams of SO2(g) at STP would be
find volume in liters
2 answers
V=nRT/P n= 17.5/molmassSO2 watch units
PV=nRT
First find moles(n) from grams/ divide number of grams given by molar mass of SO2- 17.5/64.062
Then plug it into formula with STP
T=273K P= 1 atm R is always 0.0821 with atm’s
(1)(x)=(0.27317)(0.0821)(273)
=6.12 L
First find moles(n) from grams/ divide number of grams given by molar mass of SO2- 17.5/64.062
Then plug it into formula with STP
T=273K P= 1 atm R is always 0.0821 with atm’s
(1)(x)=(0.27317)(0.0821)(273)
=6.12 L