Question

A horse trots at 10m/s for 5 s and then turns around and walks back in the other direction at 2.5m/s for 30 s.

a) what distance did the horse travel?
b) what is its displacement?
c) what is its average speed?
d) what is its average velocity?

Answer 1

forward = 50 m
then back = -75 m
a) 50 + 75
b) 50 - 75
c ) a/35
d) b/35

Answer 2

d = 10*5 + 2.5*30 = 50 + 75.

Answer 3

b. Disp. = 50 - 75 = -25 m. or 25 m below starting point.

c. r * t = 50 + 75.
r = (50 + 75)/t = (50 + 75)/35 = a/35.

d. V * t = (50 - 75)/35 = b/35.
.