Asked by Anonymous
find the 2nd derivative of x+y = xy
here is what I have so far:
1+dy/dx = x (dy/dx) + y
here is what I have so far:
1+dy/dx = x (dy/dx) + y
Answers
Answered by
Steve
so, solve for dy/dx
dy/dx (1-x) = y-1
dy/dx = (y-1)/(1-x)
dy/dx (1-x) = y-1
dy/dx = (y-1)/(1-x)
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