Asked by rhea
What is the standard form of 4x²+4y²-20x+12y-2=0
Answers
Answered by
Steve
4x²+4y²-20x+12y-2=0
4x²-20x+4y²+12y = 2
4(x²-5x) + 4(y²+3y) = 2
4(x²-5x+25/4) + 4(y²+3y+9/4) = 2 + 4*25/4 + 4*9/4
4(x-5/2)² + 4(y+3/2)² = 36
(x-5/2)² + (y+3/2)² = 9
4x²-20x+4y²+12y = 2
4(x²-5x) + 4(y²+3y) = 2
4(x²-5x+25/4) + 4(y²+3y+9/4) = 2 + 4*25/4 + 4*9/4
4(x-5/2)² + 4(y+3/2)² = 36
(x-5/2)² + (y+3/2)² = 9
Answered by
Bulbulito
why is it nine. It should be =6
Answered by
clyde dunhill
Thanks for this solution it helps me lot heheehag
Answered by
Anonymous
4x²+4y²+12y-7=0
Answered by
Brazier Kahong
4X²+4Y²+12Y-7=7
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