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Original Question
A car slows down uniformly from a speed of 24.0 m/s to rest in 4.50 s. How far did it travel in that time?Asked by Evan
A car slows down uniformly from a speed of 20.0 m/s to rest in 7.60 s. How far did it travel in that time?
Answers
Answered by
Henry2
V = Vo + a*t = 0.
20 + a*7.6 = 0,
a = -2.63 m/s^2.
d =Vo*t + 0.5a*t^2 = 20*2.63 + 0.5*(-2.63)*7.6^2 =
20 + a*7.6 = 0,
a = -2.63 m/s^2.
d =Vo*t + 0.5a*t^2 = 20*2.63 + 0.5*(-2.63)*7.6^2 =
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