Asked by ryan
A package of Toys Galore Cereal is marked "Net Wt. 12 oz." The actual weight is normally distributed, with a mean of 12 oz and a variance of 0.16.
(a) What percent of the packages will weigh less than 12 oz?
50
Correct: Your answer is correct.
%
(b) What weight will be exceeded by 2.3% of the packages? (Round your answer to one decimal place.)
12
Incorrect: Your answer is incorrect.
oz
(a) What percent of the packages will weigh less than 12 oz?
50
Correct: Your answer is correct.
%
(b) What weight will be exceeded by 2.3% of the packages? (Round your answer to one decimal place.)
12
Incorrect: Your answer is incorrect.
oz
Answers
Answered by
TOOTA
12 is correct
Answered by
nata
it is 12.4
Answered by
Bot
You are correct. To find the weight that will be exceeded by 2.3% of the packages, you need to find the z-score that corresponds to the 2.3% percentile using a standard normal distribution table or calculator.
The z-score corresponding to the 2.3% percentile is approximately -1.81.
Then, you can use the formula:
z = (x - μ) / σ
where x is the weight you want to find, μ is the mean weight (12 oz), and σ is the standard deviation (which is the square root of the variance = 0.4 oz).
Plugging in the values:
-1.81 = (x - 12) / 0.4
Solving for x:
x = -1.81 * 0.4 + 12 = 11.276
Rounding to one decimal place, the weight that will be exceeded by 2.3% of the packages is 11.3 oz.
The z-score corresponding to the 2.3% percentile is approximately -1.81.
Then, you can use the formula:
z = (x - μ) / σ
where x is the weight you want to find, μ is the mean weight (12 oz), and σ is the standard deviation (which is the square root of the variance = 0.4 oz).
Plugging in the values:
-1.81 = (x - 12) / 0.4
Solving for x:
x = -1.81 * 0.4 + 12 = 11.276
Rounding to one decimal place, the weight that will be exceeded by 2.3% of the packages is 11.3 oz.
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