Asked by Vincent
A 6.0kg block is falling toward a spring located 1.80m below. If it has a speed of 4.0m/s at that instant, what is the maximum compression of the spring if the spring constant is is 2.000 x 10^3 N/m?
Answers
Answered by
bobpursley
KE of block + PE of block=max spring energy
1/2 m v^2+mg(1.9)=1/2 *2e3*x^2
put in mass m, v velocity, g and solve for comression x.
1/2 m v^2+mg(1.9)=1/2 *2e3*x^2
put in mass m, v velocity, g and solve for comression x.
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