Asked by Plz help!
algebra readiness benchmark #2 mrs. makowsky.
1.) The area of a rectangle is 7.7682 x 10(4) cm(2) and the width is 2.42 x 10(2) cm. What is the length?
a. 3.21 x 10(2)
b. 3.21 x 10(6)
c. 1.88 x 10(8)
d. 1.88 x 10(6)
Plz help asap cause I have no clue.
I also need help w the other 35 questions if you know them lol
1.) The area of a rectangle is 7.7682 x 10(4) cm(2) and the width is 2.42 x 10(2) cm. What is the length?
a. 3.21 x 10(2)
b. 3.21 x 10(6)
c. 1.88 x 10(8)
d. 1.88 x 10(6)
Plz help asap cause I have no clue.
I also need help w the other 35 questions if you know them lol
Answers
Answered by
PsyDAG
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
Area = length * width
7.7682*10^4 = Length * 2.42*10^2
(7.7682*10^4)/(2.42*10^2) = Length
When multiplying/dividing, add/subtract exponents respectively.
Solve for length.
Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
Area = length * width
7.7682*10^4 = Length * 2.42*10^2
(7.7682*10^4)/(2.42*10^2) = Length
When multiplying/dividing, add/subtract exponents respectively.
Solve for length.
Answered by
helping :)
so is the answer a. then?
Answered by
PsyDAG
Without doing all of the division, definitely it is 10^2.
Answered by
I'm tired of Math ya'll
The correct answer is 3.21 x 10^2. I just finished the test
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.