Asked by P.Vineela
Volume of cone with base radius 1cm is22√3/21cc.Find vertical angle of cone
Answers
Answered by
bobpursley
volume=1/3 PI r^3*H
vertical angle = arcTan(H/r)
H/r=tan Theta
volume= 1/3 PI r^4 (tanTheta)
tanTheta=3*volume/(PI*r^4)
solve that.
vertical angle = arcTan(H/r)
H/r=tan Theta
volume= 1/3 PI r^4 (tanTheta)
tanTheta=3*volume/(PI*r^4)
solve that.
Answered by
Steve
I believe it's
v = 1/3 πr^2 h
so, 1/3 πr^2 h = 22√3/21
whatever that means 22√(3/21)? 22/21 √3? 22 ∛21?
and, as bobpursley said, h = r tanθ
v = 1/3 πr^2 h
so, 1/3 πr^2 h = 22√3/21
whatever that means 22√(3/21)? 22/21 √3? 22 ∛21?
and, as bobpursley said, h = r tanθ