Calculate the volume, in liters, of 5.80×10−3 mol of a gas at 44 ∘C and 0.885 atm .

2 answers

p v = n r t

convert ºC to ºK and make sure your r value has the correct units
... liters, moles, ºK, atm
1 mole occupies 22.4L at STP
You can use PV=nRT or just realize that
PV = kT, so
PV/T = k
For 1 mole, you want V such that
(1*22.4)/(273.15) = (0.885*V)/(273.15+44)
V = 29.3879 L
But you only have 0.0058 moles, so multiply V by that, and you get
V = 0.170L or 170mL