Question

The density of ice is 9.20x10² kg/m³. An ice cube which is 20.0mm high floats in water. What height of the side of the ice cube is above the surface of the water?

Answer 1

what is .92 times 20mm? That is the height below the water surface. Why does that work? Think the submerged height creates a bouyant force due to the displaced volume...Why is 90 percent of icebergs beneith the surface?

Answer 2

Hb = Di/Dw * H = Height below surface.
Di = 920 kg/m^3.
Dw = 1000 kg/m^3.
H = 20 mm.

Hb = 920/1000 * 20 = 18.4 mm.
20 - 18.4 = 1.6 mm above surface.

P.S. So, as bob said, 92%(18.4mm) is below surface.